Two Distance To Brake To Stop Formulae means the Bicycle Brake Stop Calculator calculates in each worksheet of the  Excel spreadsheet 'StoppingDistance.xls' both the Distance To Brake To Stop and Time To Brake To Stop for different example velocities, V, and gradients, G.

Stopping Sight Distance or   = Brake Reaction Distance + Brake Response Distance
Brake Reaction Distance = Velocity in metres p/s x Brake Reaction Time of 2.5 secs
Brake Response Distance = Velocity in metres p/s x Brake Response Time x Ave Braking Speed of initial V divided by 2
 2nd Distance To Brake To Stop Formula The two below Figure 19's for 'Metric units' and separately 'English Imperial units' indicate the minimum stopping sight distance (separately in km and then miles), referred to in this analysis as the Distance to Brake to Stop, for various speeds, referred to as V for velocity, and G for gradient based on a bicyclist's brake reaction time of 2.5 seconds and a Coefficient Of Friction of 0.25 to account for the poor braking equipment of many bicycles and limited skills of the majority of road cyclists when under pressure to react to an emergency braking.    At the bottom of each of the two Figure 19s are the pertinent formula.  *     The first part of each of the below two formula calcs the *     The second part of each of the below two formula calcs the  Below is an explanation of the above listed 1st Distance To Brake To Stop Formula for 5 different Velocities (speeds) between 30km p/h to 80km p/h and from a flat roadway to a 20% descent gradient which are calculated in 5 separate worksheets in  Excel spreadsheet 'StoppingDistance.xls'.  Each of those 5 worksheets also calculate the Distance to Brake to Stop using the above 2nd Distance To Brake To Stop Formula of .  Significantly, as each of the 5 worksheets show the variance between the calculations of the above described 1st Distance To Brake To Stop Formula and the 2nd Distance To Brake To Stop Formula is less than 1%. 1. Rationale to calculate the Distance to Brake to Stop for a bicycle travelling at 20km/p/h on an ascent sloping 5% - see worksheet 'stop_distance_calc 20km +5%' in 'StoppingDistance .xls' which calculates using the formula on the LHS (of the worksheet) and the formula in the above LHS Figure 19 to calculate both the Distance to Brake to Stop and the Time to Brake to Stop. 20 km/p/h is 20,000 metres per 3,600 seconds, or 5.556 metres per second. Assuming a Bicycle Brake Reaction Time of 2.5 seconds, the bicycle will travel 2.5 x  5.556 =  13.89 metres before the brakes are applied, whereupon following the Bicycle Brake Response Time, the bicycle will come to a stop upright. A Coefficient Of Friction of 0.25 means that the maximum braking force is 25% of the force that the weight of the bicycle exerts onto the road. On a flat road, the force that the weight of the bicycle plus rider exerts on the road would be the mass of the bike plus rider, times gravity (9.8 metres per second per second).  With a Coefficient Of Friction of 25%, the maximum deceleration would be 25% of 9.8 m/s/s. (Because the maximum braking force depends on the [weight of the bike plus rider] and acts against the [weight of the bike plus rider], the two "weights" cancel out.) On a 5% ascending slope, a bicycle with a Coefficient Of Friction of 0.25 can decelerate at 30% (0.25 + 5% ascending slope) of 9.8 m/s/s. That is, 2.94 m/s/s. To stop from 5.56 m/s it will take 5.556/2.94 m/p/s - that is, 1.89 seconds. If the bike starts at 5.556 m/s and decelerates at a constant rate to zero, then its average speed during deceleration is the average of 5.556 and zero. That is, 2.94 m/s. During 1.89 seconds of deceleration, at an average speed of 2.94 m/s, the bicycle will travel 5.25 metres. So with a velocity of 20 km/p/h, on a 5% gradient upwards, with a Bicycle Brake Reaction Time of 2.5 seconds, a Bicycle Brake Response Time of 2.27 seconds and a 0.25 Coefficient Of Friction, the shortest possible Distance to Brake to Stop (without skidding) is 13.89 + 5.25 = 19.14 metres during a Time to Brake to Stop of 4.39 seconds. This agrees with Figure 19 above.  It also agrees to 2.08% with the above formula in Figure 19 for km/p/h which calcs 19.54 metres to halt. 2. Rationale to calculate the Distance to Brake to Stop for a bicycle travelling at 20km/p/h on a level road - see worksheet 'stop_distance_calc 20km 0%' in 'StoppingDistance .xls' which calculates using the formula on the LHS (of the worksheet) and the formula in the above LHS Figure 19 to calculate both the Distance to Brake to Stop and the Time to Brake to Stop. 20 km/p/h is 20,000 metres per 3,600 seconds, or 5.556 metres per second. Assuming a Bicycle Brake Reaction Time of 2.5 seconds, the bicycle will travel 2.5 x  5.556 =  13.89 metres before the brakes are applied, whereupon following the Bicycle Brake Response Time, the bicycle will come to a stop upright. A Coefficient Of Friction of 0.25 means that the maximum braking force is 25% of the force that the weight of the bicycle exerts onto the road. On a flat road, the force that the weight of the bicycle plus rider exerts on the road would be the mass of the bike plus rider, times gravity (9.8 metres per second per second).  With a Coefficient Of Friction of 25%, the maximum deceleration would be 25% of 9.8 m/s/s. (Because the maximum braking force depends on the [weight of the bike plus rider] and acts against the [weight of the bike plus rider], the two "weights" cancel out.) On a flat road, a bicycle with a Coefficient Of Friction of 0.25 can decelerate at 25% of 9.8 m/s/s. That is, 2.45 m/s/s. To stop from 5.56 m/s it will take 5.556/2.45 m/p/s - that is, 2.27 seconds. If the bike starts at 5.556 m/s and decelerates at a constant rate to zero, then its average speed during deceleration is the average of 5.556 and zero. That is, 2.45 m/s. During 2.27 seconds of deceleration, at an average speed of 5.56 m/s, the bicycle will travel 6.3 metres. So on a flat road, with a Bicycle Brake Reaction Time of 2.5 seconds, a Bicycle Brake Respo3e Time of 2.27 seconds and a 0.25 Coefficient Of Friction, the shortest possible Distance to Brake to Stop (without skidding) is 13.89 + 6.30 = 20.19 metres during a Time to Brake to Stop of 4.77 seconds. This agrees with Figure 19 above.  It also agrees to 1.97% with the above formula in Figure 19 for km/p/h which calcs 20.58 metres to halt. 3. Rationale to calculate the Distance to Brake to Stop for a bicycle travelling at 40km/p/h on a level road - see worksheet 'stop_distance_calc 40km 0%' in ''StoppingDistance .xls' which calculates using the formula on the LHS (of the worksheet) and the formula in the above LHS Figure 19 to calculate both the Distance to Brake to Stop and the Time to Brake to Stop. 40 km/p/h is 40,000 metres per 3,600 seconds, or 11.11 metres per second. Assuming a Bicycle Brake Reaction Time of 2.5 seconds, the bicycle will travel 2.5 x  11.11 =  27.78 metres before the brakes are applied, whereupon following the Bicycle Brake Response Time, the bicycle will come to a stop upright. A Coefficient Of Friction of 0.25 means that the maximum braking force is 25% of the force that the weight of the bicycle exerts onto the road. On a flat road, the force that the weight of the bicycle plus rider exerts on the road would be the mass of the bike plus rider, times gravity (9.8 metres per second per second). With a Coefficient Of Friction of 25%, the maximum deceleration would be 25% of 9.8 m/s/s. (Because the maximum braking force depends on the [weight of the bike plus rider] and acts against the [weight of the bike plus rider], the two "weights" cancel out.) On a flat road, a bicycle with a Coefficient Of Friction of 0.25 can decelerate at 25% of 9.8 m/s/s. That is, 2.45 m/s/s. To stop from 11.11 m/s it will take 11.11/2.45 m/p/s - that is, 4.54 seconds. If the bike starts at 11.111 m/s and decelerates at a constant rate to zero, then its average speed during deceleration is the average of 11.111 and zero. That is, 5.56 m/s. During 4.54 seconds of deceleration, at an average speed of 2.45 m/s, the bicycle will travel 25.195 metres. So on a flat road, with a Bicycle Brake Reaction Time of 5.56 seconds, a Bicycle Brake Response Time of 4.54 seconds and a 0.25 Coefficient Of Friction, the shortest possible Distance to Brake to Stop (without skidding) is 27.78 + 25.19 = 52.97 metres during a Time to Brake to Stop of 7.04 seconds. This agrees with Figure 19 above.  It also agrees to 1.5% with the above formula in Figure 19 for km/p/h which calcs 53.77 metres to halt. 4. Rationale to calculate the Distance to Brake to Stop for a bicycle travelling at 30km/p/h on a descent sloping 10% - see worksheet 'stop_distance_calc 30km -10%' in ''StoppingDistance .xls' which calculates using the formula on the LHS (of the worksheet) and the formula in the above Figure 19 to calculate both the Distance to Brake to Stop and the Time to Brake to Stop. 30 km/p/h is 30,000 metres per 3,600 seconds, or 8.33 metres per second. Assuming a Bicycle Brake Reaction Time of 2.5 seconds, the bicycle will travel 2.5 x  8.33 =  20.83 metres before the brakes are applied, whereupon following the Bicycle Brake Response Time, the bicycle will come to a stop upright. A Coefficient Of Friction of 0.25 means that the maximum braking force is 25% of the force that the weight of the bicycle exerts onto the road. On a 10% descent slope flat road, the force that the weight of the bicycle plus rider exerts on the road would be the mass of the bike plus rider, times gravity (9.8 metres per second per second). With a Coefficient Of Friction of 25%, the maximum deceleration would be 25% of 9.8 m/s/s. (Because the maximum braking force depends on the [weight of the bike plus rider] and acts against the [weight of the bike plus rider], the two "weights" cancel out.) On a 10% descending slope, a bicycle with a Coefficient Of Friction of 0.25 can decelerate at 15% (25% less10% slope) of 9.8 m/s/s.  That is, 1.47 m/s/s. To stop from 8.33 m/s it will take 8.33/1.47 m/p/s - that is, 5.67 seconds. If the bike starts at 8.33 m/s and decelerates at a constant rate to zero, then its average speed during deceleration is the average of 8.33 and zero. That is, 4.167 m/s. During 5.67 seconds of deceleration, at an average speed of 4.167 m/s, the bicycle will travel 23.62 metres. So with a velocity of 30 km/p/h, on a 10% gradient downwards, with a Bicycle Brake Reaction Time of 2.5 seconds, a Bicycle Brake Response Time of  5.67 seconds and a 0.25 Coefficient Of Friction, the shortest possible Distance to Brake to Stop (without skidding) is 20.83 + 23.62 = 44.45 metres during a Time to Brake to Stop of 8.17 seconds.  This agrees with Figure 19 above.   It also agrees to 1.34% with the above formula in Figure 19 for km/p/h which calcs 45.05 metres to halt. 5. Rationale to calculate the Distance to Brake to Stop for a bicycle travelling at 50km/p/h on a descent sloping 20% - see worksheet 'stop_distance_calc 50km -20%' in ''StoppingDistance .xls' which calculates using the formula on the LHS (of the worksheet) and the formula in the above LHS Figure 19 to calculate both the Distance to Brake to Stop and the Time to Brake to Stop. 50 km/p/h is 50,000 metres per 3,600 seconds, or 13.89 metres per second. Assuming a Bicycle Brake Reaction Time of 2.5 seconds, the bicycle will travel 2.5 x  13.89 =  34.72 metres before the brakes are applied, whereupon following the Bicycle Brake Response Time, the bicycle will come to a stop upright. A Coefficient Of Friction of 0.25 means that the maximum braking force is 25% of the force that the weight of the bicycle exerts onto the road. On a 20% descent slope flat road, the force that the weight of the bicycle plus rider exerts on the road would be the mass of the bike plus rider, times gravity (9.8 metres per second per second).  With a Coefficient Of Friction of 25%, the maximum deceleration would be 25% of 9.8 m/s/s. (Because the maximum braking force depends on the [weight of the bike plus rider] and acts against the [weight of the bike plus rider], the two "weights" cancel out.) On a 20% descending slope, a bicycle with a Coefficient Of Friction of 0.25 can decelerate at 5% (25% less 20% slope) of 9.8 m/s/s.  That is, 0.49 m/s/s. To stop from 13.89 m/s it will take 13.89/0.49 m/p/s - that is, 28.34 seconds. If the bike starts at 13.89 m/s and decelerates at a constant rate to zero, then its average speed during deceleration is the average of 13.89 and zero. That is, 6.944 m/s. During 28.34 seconds of deceleration, at an average speed of 6.944 m/s, the bicycle will travel 196.84 metres. So with a velocity of 50 km/p/h, on a 20% gradient downwards, with a Bicycle Brake Reaction Time of 2.5 seconds, a Bicycle Brake Response Time of  28.34 seconds and a 0.25 Coefficient Of Friction, the shortest possible Distance to Brake to Stop (without skidding) is 34.72 + 196.84 = 231.56 metres during a Time to Brake to Stop of 30.84 seconds.  This agrees with Figure 19 above.  It also agrees to less than 1% with the above formula in Figure 19 for km/p/h which calcs 232.56 metres to halt. 6. Rationale to calculate the Distance to Brake to Stop for a bicycle travelling at 70km/p/h on a descent sloping 12% - see worksheet 'stop_distance_calc 70km -12%' in ''StoppingDistance .xls' which calculates using the formula on the LHS (of the worksheet) and the formula in the above LHS Figure 19 both the Distance to Brake to Stop and the Time to Brake to Stop. 70 km/h is 70,000 metres per 3,600 seconds, or 19.44 metres per second. Assuming a Bicycle Brake Reaction Time of 2.5 seconds, the bicycle will travel 2.5 x  19.44 =  48.61 metres before the brakes are applied, whereupon following the Bicycle Brake Response Time, the bicycle will come to a stop upright. A Coefficient Of Friction of 0.25 means that the maximum braking force is 25% of the force that the weight of the bicycle exerts onto the road. On a 12% descent slope flat road, the force that the weight of the bicycle plus rider exerts on the road would be the mass of the bike plus rider, times gravity (9.8 metres per second per second). With a Coefficient Of Friction of 25%, the maximum deceleration would be 25% of 9.8 m/s/s. (Because the maximum braking force depends on the [weight of the bike plus rider] and acts against the [weight of the bike plus rider], the two "weights" cancel out.) On a 12% descending slope, a bicycle with a Coefficient Of Friction of 0.25 can decelerate at 13% (25% less12% slope) of 9.8 m/s/s.  That is, 0.98 m/s/s. To stop from 19.44 m/s it will take 19.44/1.24 seconds - that is, 15.26 seconds. If the bike starts at 19.44 m/s and decelerates at a constant rate to zero, then its average speed during deceleration is the average of 19.44 and zero. That is, 9.722 m/s. During 22.68 seconds of deceleration, at an average speed of 11.11 m/s, the bicycle will travel 251.95 metres. So with a velocity of 70 km/p/h, on a 12% gradient downwards, with a Bicycle Brake Reaction Time of 2.5 seconds, a Bicycle Brake Response Time of 15.26 seconds and a 0.25 Coefficient Of Friction, the shortest possible Distance to Brake to Stop (without skidding) is 48.61 + 148.39 = 197.51 metres during a Time to Brake to Stop of 17.76 seconds.  This is not able to be corroborated with Figure 19 above because that Figure 19 does not calc beyond 50 km/p/h.  However, it agrees to less than 1% with the above formula in Figure 19 for km/p/h which shows calcs 198.39 metres to halt. 7. Rationale to calculate the Distance to Brake to Stop for a bicycle travelling at 80km/p/h on a descent sloping 15% - see worksheet 'stop_distance_calc 80km -15%' in ''StoppingDistance .xls' which calculates using the formula on the LHS (of the worksheet) and the formula in the above LHS Figure 19 to calculate both the Distance to Brake to Stop and the Time to Brake to Stop. 80 km/h is 80,000 metres per 3,600 seconds, or 22.22 metres per second. Assuming a Bicycle Brake Reaction Time of 2.5 seconds, the bicycle will travel 2.5 x  22.22 =  55.56 metres before the brakes are applied, whereupon following the Bicycle Brake Response Time, the bicycle will come to a stop upright. A Coefficient Of Friction of 0.25 means that the maximum braking force is 25% of the force that the weight of the bicycle exerts onto the road. On a 15% descent slope flat road, the force that the weight of the bicycle plus rider exerts on the road would be the mass of the bike plus rider, times gravity (9.8 metres per second per second). With a Coefficient Of Friction of 25%, the maximum deceleration would be 25% of 9.8 m/s/s. (Because the maximum braking force depends on the [weight of the bike plus rider] and acts against the [weight of the bike plus rider], the two "weights" cancel out.) On a 15% descending slope, a bicycle with a Coefficient Of Friction of 0.25 can decelerate at 10% (25% less15% slope) of 9.8 m/s/s.  That is, 0.98 m/s/s. To stop from 22.22 m/s it will take 22.22/0.98 seconds - that is, 22.68 seconds. If the bike starts at 22.22 m/s and decelerates at a constant rate to zero, then its average speed during deceleration is the average of 22.22 and zero. That is, 11.11 m/s. During 22.68 seconds of deceleration, at an average speed of 11.11 m/s, the bicycle will travel 251.95 metres. So with a velocity of 80 km/p/h, on a 15% gradient downwards, with a Bicycle Brake Reaction Time of 2.5 seconds, a Bicycle Brake Response Time of  22.68 seconds and a 0.25 Coefficient Of Friction, the shortest possible Distance to Brake to Stop (without skidding) is 55.56 + 251.95 = 307.51 metres during a Time to Brake to Stop of 25.18 seconds.   This is not able to be corroborated with Figure 19 above because that Figure 19 does not calc beyond 50 km/p/h.  However, it agrees to less than 1% with the above formula in Figure 19 for km/p/h which calcs 309.11 metres to halt.

On a road sloping downhill at -

*           20%, with a 0.25 Coefficient Of Friction, most of the braking force will be absorbed by counteracting gravity, thereby leaving relatively little of the braking force available to slow the bike, so it will take a very long time to stop.

*           25%, with a 0.25 Coefficient Of Friction, the entire braking force will be needed to counteract the gravitational acceleration, the bike will continue at a constant speed and the braking distance will be infinite.

However, the above calcs make no allowance that a heavier cyclist will take longer to brake to a halt than a lighter cyclist.

In dry conditions a heavier cyclist will take longer to stop than a lighter cyclist. This is because the Coefficient Of Friction will be higher, and thus allow higher braking forces. These higher braking forces will cause the brakes to heat up and fade, or cause the brake pads or the rubber on the tyre to start to shred. In wet conditions the braking forces will be lower and the brakes will be less likely to overheat.

Sight Distance - pg 40 of 'Guide for development of bicycle facilities" notes:

The distance required to bring a bicycle to a full controlled stop is a function of the -

i)         bicyclist’s perception time;

ii)        bicyclist's brake reaction time,

iii)       initial speed of the bicycle, known as V

iv)       coefficient of friction between the tires and the pavement - known as f, and

v)        braking ability of the bicycle and rider, known as Ab.

Four other variables which affect the Distance to Brake to Stop and the  are the -

vi)        gradient of road ahead during Distance to Brake to Stop known as G

vii)       weight of the bicycle and rider, known as M; and

viii)      direction of road ahead during Distance to Brake to Stop known as Dir;

viii)       wind direction and strength, known as W.

The above are known as the Eight Bicycle Variables To Stop.

The two below Figure 19 indicates the minimum stopping sight distance (separately in km and then miles), referred to in this analysis as the Distance to Brake to Stop, for various design speeds and grades based on a bicyclist's brake reaction time of 2.5 seconds and a Coefficient Of Friction of 0.25 to account for the poor braking equipment of many bicycles and limited skills of.

As noted in -

(A)        presently the Bicycle Brake Stop Calculator -

(a)        assumes a constant Mass of the cyclist is 150lbs (68.1kgs) and assumes a f of 35%;

(b)        factors in only the variables of speed V and gradient G.

(c)        does not factor in the variables 4, 5, 6 and 7 of the Eight Bicycle Variables To Stop.  These are:

1. direction of road ahead (between 0 degrees and 90 degrees) is Dir

2. bicycle/cyclist weight = Mass is M

3. wind speed impact is W

4. braking ability of the bicycle and rider is Ab

(B)         It should be possible to incorporate the above 'missing' variables to test the Two Distance To Brake To Stop Formulae.

High Speed Bicycling by Wayne Pein wpein@nc.rr.com (Revised July 2007) notes that according to AASHTO’s “Green Book,”A Policy on Geometric Design of Highways and Streets, in roadway design, braking and sight distance calculations for all vehicles, including bicycles, are figured using a deceleration rate of 3.4 m/s2 (11.2 ft/s2), which is 0.35 g.

Four-wheeled motor vehicles have much better emergency braking capabilities than bicycles, approximately 0.6 - 0.7 g (some cars can achieve more than 0.9 g), affording motorists a great margin for error beyond AASHTO’s roadway design specification. In contrast, a typical bicyclist can be expected to decelerate at 0.35 g on clean, dry, level pavement which, coincidentally, is AASHTO’s figure for roadway design purposes as previously noted.  A conventional bicycle's theoretical maximum deceleration is limited to about 0.6 g on level pavement by weight transfer, which can cause pitch-over. However, only a highly skilled bicyclist using optimal technique may be able to achieve this 0.6 g; most will be far lower at about 0.35 g.

For non-level roads the grade is added (+ or -) to this deceleration rate in gees. This means that on a 5% descent, for example, braking effort equivalent to 0.05 g is used to counteract the effect of gravity, leaving typical bicyclists only 0.35 - 0.05 = 0.30 g for deceleration.

Further, unlike motor vehicle braking which is not markedly affected in wet conditions, the braking capability of some bicycles is greatly reduced due to the diminished friction between the brake shoes and a wet rim. According to John Forester [personal communication, 12/22/04] “Bicycle braking under wet conditions needs to be considered in two phases. The first phase is wiping the rims clean, the second phase is actual braking. For aluminium rims, one can consider three rotations of the wheel to wipe the rim reasonably dry. That is about 21 feet for typical wheel sizes. Subsequent braking, given good brakes to start with, is then typical of dry, unless the road surface is so slippery that it will not produce a 0.67 Coefficient Of Friction. The situation with chrome-plated steel rims is worse; they don't wipe dry.”

At 20 mph (29 ft/s), 21 feet of nearly nonexistent braking adds about 0.7 seconds to braking time. Thus, instead of taking 2.6 seconds to come to a complete stop, it would take 3.3 seconds on level ground when wet, amounting to an average deceleration of 0.28 g. Heavy rain or road splash at high speed could result in continuously wet rims, further drastically reducing braking capacity.

For sight-triangle and other operational calculations, bicycle deceleration rate in wet conditions should be considered to be slightly more than half that under dry conditions; 0.20 g.

Moreover, BL stripes are very slippery when wet, adding an unnecessary longitudinal hazard.

These concerns amplify the argument that BLs are counter-indicated, especially on high speed descents.

NOTES ON RESISTANCE AND POWER IN CYCLING

The standard model for calculating the resistance to motion of bicycles, using pounds, feet, and seconds, is:

Resistance (lbs) = Slope Resistance + Rolling Resistance + Air Resistance

Slope Resistance =Mass * Slope

Rolling Resistance =Bearing Friction + Tire Losses (both empirically determined)

Air Resistance =Density of air/2 * Cross Sectional Area * Drag Factor * Speed * Speed

The accepted standard density of air at sea level is 0.002378 slugs/cu.ft. (Which equals 0.07657 lbs/cu.ft)

The FHWA research done in Davis (FHWA-RD-75-112) gives the following resistances when using a system that uses pounds and hours and mixes feet with miles:

Resistance, lbs (FHWA) =Weight*Slope + Weight*(0.005 + 0.15/TirePressure) +

0.00256*(AirSpeed*AirSpeed*DragArea* DragFactor)

The 0.00256 factor converts the 0.002378 by combining the division by 2 and the conversion from feet per second to miles

per hour. Also, their values for bearing and tire friction are high relative to what is available today. Good wired-on tires

have improved greatly since then. The CycSpeed program reflects this change by using bearing friction of 0.002 and tire

losses as 0.10/TirePressure.

Whitt and Wilson give the following for typical drag areas and factors:

Cyclist on roadster bicycle: 5.3 Square Feet and 1.2 Drag Factor

Cyclist on sporting bicycle: 4.3 Square Feet and 1.0 Drag Factor

Cyclist on racing bicycle: 3.55 Square Feet and 0.9 Drag Factor

The resistance to acceleration (inertia) is greater than the mass by an amount very nearly equal to the mass of the tires

and rims. CycSpeed adds in the masses of the tires and rims. Whitt & Wilson call this the WheelResistanceFactor and

typically give it a value of 0.01 for all bicycles.

Whitt & Wilson give the following for resistance using metric (MKS) system:

Res (newtons) = Mg(Rolling Resistance + Slope Resistance + Wheel Resistance Factor) +

0.5*(Drag Factor*Drag Area*Air Density*Airspeed*Airspeed)

=Mg*(Cr + slope + a/g*1.01) + 0.5*Cd*A*R*(Vc + Vw)*(Vc + Vw)

=Mg*(Cr + slope + a/g*1.01) + 0.5*1.0*0.4*1.226*V*V

=K1 + K2V*V +10.32M(slope +a/g*1.01)

Where K1 and K2 are per the following:

K1 K2

Roadster bicycle 7.845 0.3872

Sports bicycle 3.509 0.2581

Racing bicycle 2.508 0.1916